this post was submitted on 20 May 2025
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[–] BombOmOm@lemmy.world 21 points 2 weeks ago* (last edited 2 weeks ago) (5 children)

Edit 2: Eheran pointed out I screwed up the math. Correct total energy output is 13μWh. A very, very, very small amount of energy.

(2x10^15^ W) * (25s/1x10^18^) * (1 h/ 3600 s) = 13μWh


Previous bad math:

spoiler

~~The key thing here is the burst lasted for "25 quintillionths of a second long". Meaning it had a total output energy of 180 W/h, or how much energy a standard US space heater (1.5KW) outputs if it was on for 7.2 minutes.~~

~~That is a pretty impressive amount of power coming in instantly to a small spot. Would leave basically zero time for it to dissipate into surrounding materials.~~

~~Edit: Fixed the math. (I hope)~~ ~~(2x10^15^ W) * (25/1x10^18^ s) * (3600 s / 1 h) = 180W/h~~

[–] Eheran@lemmy.world 6 points 2 weeks ago (1 children)

You multiply seconds with seconds per hour and somehow get "per hour" as the final result? But even ignoring that error, what is W/h supposed to be? Rate of change of power?

[–] Eheran@lemmy.world 2 points 2 weeks ago (1 children)

You multiply seconds with seconds per hour and somehow get "per hour" as the final result? But even ignoring that error, what is W/h supposed to be? Rate of change of power?

Also, it is a small k for kilo and you don't write it as 4.310^18^[unit]. Just 4.310^18 [unit]. Or 4.3E18 [unit].

[–] BombOmOm@lemmy.world 2 points 2 weeks ago* (last edited 2 weeks ago)

Crap, you are right, units should be in Wh not W/h and as a result I put the conversion to hours backwards. Well, that turns the whole thing from an impressive amount of energy to basically none!

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