this post was submitted on 11 Dec 2025
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Rust

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[–] thingsiplay@beehaw.org 0 points 1 week ago (3 children)

I don't understand why this never type was introduced at all. Instead functions not returning, shouldn't Rust enforce returning from function and instead use a None in place of never type? Otherwise how will the "Unwinding" of program flow implemented?

[–] 0xDEADBEEFCAFE@programming.dev 10 points 1 week ago (1 children)

shouldn’t Rust enforce returning from function

How do you enforce returning from exit or a function with a loop that never terminates?

[–] thingsiplay@beehaw.org 1 points 1 week ago (1 children)

If it never terminates, then it means it runs forever.

[–] 0xDEADBEEFCAFE@programming.dev 13 points 1 week ago

Right, so you can't "enforce" a return from the function.

[–] SorteKanin@feddit.dk 7 points 1 week ago

shouldn’t Rust enforce returning from function

This is impossible. How would you enforce that? What prevents a function from panicking, aborting the whole process or just going into an infinite loop? All these things correspond to the never type.

I think you're misunderstanding what the never type is. It's not equivalent to None at all. It's a type that doesn't have any values. This is useful in situations with generic code where for example an error type can be chosen as the never type. Then you could destructure or unwrap a Result without handling the error, cause the type system guarantees the error never occurs.

I think you should read up on the never type a bit more. It's a perfectly natural part of the type system. In fact you can make your own very easily: enum Never {}

[–] TehPers@beehaw.org 4 points 1 week ago (1 children)

I don't know where None comes from (what's the T in Option<T>?)

Assuming you meant (), that's a unit type with one valid value. It's a ZST, but can be created and returned.

! is a bottom type. It's uninhabited. Can't be created. Functions can never return it because they can never construct it. So why's this useful? It can be coerced to any type.

Because the set of valid values for ! is the null set, by contradiction, there do not exist any values valid for the type ! that are invalid for any other type T. Therefore, all valid values of ! are also valid values of any other type T, and you can always convert from it to any other type.

Notably, this is already possible, but language support for it isn't amazing:

enum A {}

fn bar(a: A) {
    let foo: Box<Arc<Rc<Mutex<String>>>> = match a {}
}

Heck you can even do this today:

// `loop {}` never returns, so its type is `!`:
let blah: String = loop {};
[–] thingsiplay@beehaw.org 0 points 1 week ago (1 children)

To me it makes no sense. Because if it never returns, then it has no return value. Therefore it makes no sense to have a type for something that does not exist.

[–] TehPers@beehaw.org 8 points 1 week ago (1 children)

Because if it never returns, then it has no return value.

Then how would you annotate having no return value?

[–] thingsiplay@beehaw.org 0 points 1 week ago (1 children)

I guess it makes sense. What I struggled with is, as the type is unusable basically and I didn't like the idea it being a type. But for documentation reasons, it makes sense. Otherwise, it has no practical meaning. Even a comment could have the same effect.

[–] TehPers@beehaw.org 6 points 1 week ago

The never type comes more from type theory and isn't common in other languages (though TS has never). Similar to 0 or the null set, it exists as a "base case" for types. For example, where you have unions of T1 | T2 | ..., the "empty union" is the never type. Similarly, for set theory, a union of no sets is the null set, and in algebra, the summation of no numbers is 0.

In practice, because it can't be constructed, it can be used in unique ways. These properties happen to be super useful in niche places.