Max11 is all my code. Why doesn't it work????π€
this post was submitted on 22 Oct 2023
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hereβs another mathematical approach (that has the added benefit of only working when x and y are both positive).
let f denote the linear functional on β^2^ defined by f(1,0) = x and f(0,1) = y (and extend by linearity). then the operator norm || f || is equal to max(x,y).
Why use
const max = (x, y) => x > y ? x : y
instead of
function max(x, y) { return x > y ? x : y } ?
I'm mostly lost and in over my head
my $max = $x > $y ? $x : $y;