this post was submitted on 21 Mar 2024
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Science Memes

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[–] OpenStars@startrek.website 58 points 1 year ago

Hrm, it sounds like the teacher already knew the answer.

Maybe stop wasting the time of the student then!?

You're welcome.

[–] Dave@lemmy.nz 53 points 1 year ago (2 children)

Can someone explain this to me? Not the maths, the joke.

[–] fossilesque@mander.xyz 42 points 1 year ago (2 children)
[–] LinkOpensChest_wav@lemmy.blahaj.zone 9 points 1 year ago (1 children)

Old man voice: "Aunt eye memes? In my day, we only had regular memes, and I turned out fine!"

[–] Venator@lemmy.nz 3 points 1 year ago

I prefer large memes

[–] driving_crooner@lemmy.eco.br 19 points 1 year ago* (last edited 1 year ago) (1 children)

The test:

Solve e^{int_0 1 x2+x+1 dx}^

[–] Usernamealreadyinuse@lemmy.world 2 points 1 year ago* (last edited 1 year ago)

No, copilot solve this test

Answer:

To solve the expression ( e^{\int_0^1 x^2+x+1 , dx} ), we first need to calculate the integral of ( x^2+x+1 ) from 0 to 1.

The integral of ( x^2+x+1 ) is: [ \int x^2+x+1 , dx = \frac{x^3}{3} + \frac{x^2}{2} + x + C ]

Evaluating this from 0 to 1 gives us: [ \left[ \frac{x^3}{3} + \frac{x^2}{2} + x \right]_0^1 = \left( \frac{1}{3} + \frac{1}{2} + 1 \right) - \left( 0 + 0 + 0 \right) = \frac{11}{6} ]

Now, we raise ( e ) to the power of this result: [ e^{\frac{11}{6}} ]

This is the solution to the given expression. If you need a numerical approximation, ( e^{\frac{11}{6}} ) is approximately 4.953.

...and this student was Albert Einstein