Couldn't that be a 2d projection of a tetrahedron standing on one of its edges?
this post was submitted on 13 Sep 2023
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Yeah, you just need to get the third dimension involved to make it work. Pythagoras would be fine with it.
8.48 feef for those wondering
feef
Feef on the ground, teef in your 'ead. That's how I remember it and it hasn't steered me wrong yet.
6 feef = 0 feet
Easy as that
Well ain't this place a geographical oddity. Six feet from everywhere!
Maybe 6 feef isn't about space but time and the lower two people are the same but at different points in time?
You're not reading it right. The bottom label says 6 feef. Clearly this is some sort of measurement of 4th dimensional movement that accounts for the other measurements.
Minimum. This is obviously saying keep a minimum of 6-feet of distance in each direction. Who would ever recommend either an exact distance or a maximum safe distance!?
Could it be done if they are in a 3d plane?
No, but it'd work if it were a 3D shape. A plane is flat, even in 3D space.
I’ve been on a plane before and it definitely wasn’t flat
Are you sure you're not flat yourself?
If the earth is flat, how can a plane be not flat?
So a cube? 0.0 and 1.1 are on a top side and 0.1 and 1.0 are on a bottom side so every line is a diagonal of a cube's face
A cube needs 3 coordinates, 0.0.0 to one corner, 1.1.1 to the opposite one. And its size is square root of 3 (if the diagonal of a 2d square is square root of 2, and the one of the cube is square root of 3, can be said that the diagonal of a n dimension cube is square root of n?)
Wow ! Its a shame everything else in the picture is absolutely true to reality and the distances spoil the realism!